| Substance | Specific heat |
| A | \[0.60\,\,J{{g}^{-1}}\,{{\,}^{o}}{{C}^{-1}}\] |
| B | \[0.40\,\,J{{g}^{-1}}\,{{\,}^{o}}{{C}^{-1}}\] |
| C | \[0.20\,\,J{{g}^{-1}}\,{{\,}^{o}}{{C}^{-1}}\] |
A) \[{{T}_{C}}>{{T}_{B}}>{{T}_{A}}\]
B) \[{{T}_{B}}>{{T}_{A}}>{{T}_{C}}\]
C) \[{{T}_{A}}>{{T}_{B}}>{{T}_{C}}\]
D) \[{{T}_{A}}={{T}_{B}}={{T}_{C}}\]
Correct Answer: A
Solution :
Specific heat, \[c=\frac{Q}{m\,.\,\,\Delta \,T}\] \[=\frac{Q}{m\,({{T}_{2}}-{{T}_{1}})}\] Except specific heat and final temperature, all other conditions are same in case of substances A, B and C. Thus, final temperature depends only upon specific heat. Since, the order of specific heats of substances \[\underset{\left( 0.60 \right)}{\mathop{A}}\,\,\,\,\,>\,\,\,\,\underset{\left( 0.40 \right)}{\mathop{B}}\,\,\,\,\,>\,\,\,\,\underset{\left( 0.20 \right)}{\mathop{C}}\,\] \[\therefore \] The order of the final temperature is \[{{T}_{C}}>{{T}_{B}}>{{T}_{A}}\]
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