A) 20/g
B) 20 g
C) 20\[\sqrt{2}\]/g
D) 20\[\sqrt{2}\]g
Correct Answer: C
Solution :
Given \[u=20\,m/s\] and \[\theta ={{45}^{o}}\] Time taken by the object return to the same level at \[\theta ={{45}^{o}}\] is maximum \[T=\frac{\sqrt{2}\,u}{g}\]You need to login to perform this action.
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