A) \[O_{2}^{+}\]
B) \[O_{2}^{0}\]
C) \[O_{2}^{-}\]
D) \[O_{2}^{2-}\]
Correct Answer: A
Solution :
Bond order in \[O_{2}^{+}=\frac{1}{2}(8-3)=2.5\] Bond order in \[{{O}_{2}}=\frac{1}{2}(8-4)=2\] Bond order in \[O_{2}^{-}=\frac{1}{2}(8-5)=1.5\] Bond order in \[O_{2}^{2-}=\frac{1}{2}(8-6)=1\] Higher the bond order, greater the bond energy because of the smaller bond length.You need to login to perform this action.
You will be redirected in
3 sec