A) acetone
B) diethylketone
C) formaldehyde
D) benzaldehyde
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-H+N{{H}_{2}}OH\xrightarrow{{}}\]\[\underset{benzaldehyde\text{ }oxime}{\mathop{{{C}_{6}}{{H}_{5}}CH=NOH}}\,\] It shows geometrical isomerism. Syn antiYou need to login to perform this action.
You will be redirected in
3 sec