DUMET Medical DUMET Medical Solved Paper-2011

  • question_answer
    A Carnot engine has efficiency 25%. It operates between reservoirs of constant temperatures with temperature difference of 80°C. What is the temperature of the low-temperature reservoir?

    A)  \[-25{}^\circ C\]          

    B)  \[25{}^\circ C\]

    C)  \[-33{}^\circ C\]

    D)  \[33{}^\circ C\]

    Correct Answer: C

    Solution :

    Efficiency \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] \[\frac{25}{100}=\frac{{{T}_{1}}-({{T}_{1}}-80)}{{{T}_{1}}}\] \[\frac{1}{4}=\frac{80}{{{T}_{1}}}\] \[{{T}_{1}}=320\,\,K\] \[{{T}_{1}}=320-273={{47}^{o}}C\] The temperature of the low temperature reservair = 47 - 80 \[=-{{33}^{o}}C\]


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