A) 1.6\[\Omega \]
B) 13.5\[\Omega \]
C) 1250\[\Omega \]
D) 10.6\[\Omega \]
Correct Answer: D
Solution :
Given, \[V=115\,V\] and \[P=1250\,W\] We know, \[R=\frac{{{V}^{2}}}{P}\] So, \[R=\frac{{{(115)}^{2}}}{1250}\] \[=10.58\,\,\Omega \] \[R=10.6\,\,\Omega \]
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