A) \[{{H}_{5}}{{C}_{2}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-Br\]
B) \[C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-Br\]
C) \[H-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ {{C}_{2}}{{H}_{5}} \end{smallmatrix}}{\mathop{C}}\,}}\,-Br\]
D) \[H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]
Correct Answer: D
Solution :
The overall order of reactivity in \[{{S}_{{{N}^{2}}}}\] reactions is Methyl halides > primary halides > secondary halides > tertiary halides. Thus, among the given compounds primary alkyl halides undergo So reaction most rapidly.
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