A) \[{{H}_{2}}/Pt\]
B) Zn-Hg/HCl
C) \[Li/N{{H}_{3}}\]
D) \[NaB{{H}_{4}}\]
Correct Answer: D
Solution :
Sodium borohydride is more specific for the reduction of aldehydes and ketones. It is a milder reducing agent. It reduces only aldehydes and ketones and has no effect on\[C=C,\,C\equiv C,\,\,N=N\], ester, nitriles and nitro groups.
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