A) \[{{K}_{3}}={{K}_{1}}+{{K}_{2}}\]
B) \[{{K}_{3}}={{K}_{1}}{{K}_{2}}\]
C) \[{{K}_{3}}={{K}_{1}}/{{K}_{2}}\]
D) \[{{K}_{3}}={{K}_{2}}/{{K}_{1}}\]
Correct Answer: B
Solution :
\[{{I}_{2}}(aq){{I}_{2}}\] (oil); Equilibrium constant \[={{K}_{1}}\] \[{{I}_{2}}\] (oil) \[{{I}_{2}}\] (ether); Equilibrium constant \[={{K}_{2}}\] \[{{I}_{2}}(aq){{I}_{2}}\] (ether); Equilibrium constant \[={{K}_{3}}\] The values of \[{{K}_{1}},{{K}_{2}}\] and \[{{K}_{3}}\] are \[{{K}_{1}}=\frac{{{I}_{2}}(oil)}{{{I}_{2}}(aq)};\,{{K}_{2}}=\frac{{{I}_{2}}(ether)}{{{I}_{2}}(oil)};{{K}_{3}}=\frac{{{I}_{2}}(ether)}{{{I}_{2}}(aq)}\] \[\therefore \] \[{{K}_{3}}={{K}_{1}}{{K}_{2}}\]
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