question_answer

The geometry of electron pairs around I in \[I{{F}_{5}}\] is

A)  octahedral

B)  trigonal bipyramidal

C)  square pyramidal

D)  pentagonal planar

Correct Answer: A

Solution :

Hybridisation in \[I{{F}_{5}}=\frac{1}{2}[7+5-0+0]=6;\] Hence, \[s{{p}^{3}}{{d}^{2}}\] hybridisation exists in \[I{{F}_{5}}\]. Octahedral geometry with one position occupied by a lone pair of electrons.