A) \[S{{e}^{2-}}\]
B) \[{{F}^{-}}\]
C) \[{{O}^{2-}}\]
D) \[R{{b}^{+}}\]
Correct Answer: A
Solution :
Being isoelectronic, greater the nuclear charge, smaller the size and lesser the nuclear charge, larger the size. \[\underset{(A.N.=8)}{\mathop{{{O}^{2-}}}}\,\,\,\,\,\,>\,\,\,\,\underset{(A.N.=9)}{\mathop{{{F}^{-}}}}\,\] (10 electrons) \[\underset{(A.N.=34)}{\mathop{S{{e}^{2-}}}}\,\,\,\,\,>\,\,\,\,\underset{(A.N.=37)}{\mathop{R{{b}^{+}}}}\,\] electrons) \[\therefore \,\,\,S{{e}^{2-}}\] has largest radius.
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