A) \[{{H}_{2}}S\]
B) \[H{{S}^{-}}\]
C) \[{{S}^{2-}}\]
D) \[{{H}_{2}}O\]
Correct Answer: C
Solution :
\[{{H}_{2}}S,\,\,H{{S}^{-}}\] and \[{{H}_{2}}O\] can accept as well as donate a proton, thus, behave as both a Bronsted acid and Bronsted base. Whereas \[{{S}^{2-}}\] can accept a proton only, thus behaves only as a Bronsted base or Lewis base.
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