A) 25
B) 50
C) 2500
D) \[4\times {{10}^{-4}}\]
Correct Answer: C
Solution :
\[AB;{{K}_{1}}=2\] ?. (i) Reaction (i) is multiplied by 2; \[2A2B;{{K}_{1}}={{(2)}^{2}}=4\] ... (ii) Similarly, \[BC;{{K}_{2}}=0.01\] ... (iii) Reaction (iii) is multiplied by 2; \[2A2C;{{K}_{2}}={{(0.01)}^{2}}={{10}^{-4}}\] ?. (iv) Adding (ii) and (iv) \[2A2C;{{K}_{3}}={{K}_{1}}\times {{K}_{2}}=4\times {{10}^{-4}}\] or \[2C2A;{{K}_{3}}=\frac{1}{4\times {{10}^{-4}}}\] \[=\frac{10000}{4}=2500\]
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