A) 6J
B) 8J
C) 10 J
D) 12 J
Correct Answer: A
Solution :
Given \[F=x+{{x}^{3}}\] and \[x=0\] to \[x=2\,m\] We know \[W=\int{Fdx}\] \[W=\int_{0}^{2}{(x+{{x}^{3}})dx}\] \[W=\left[ \frac{{{x}^{2}}}{2}+\frac{{{x}^{4}}}{4} \right]_{0}^{2}\] \[W=\left[ \frac{4}{2}+\frac{16}{4} \right]\] \[W=6\,J\]
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