A) One
B) Two
C) Three
D) Four
Correct Answer: D
Solution :
Structure of 2-methylbutane \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}\] Since there are four different types of hydrogen, thus four types of isomers are obtained. \[\underset{1-bromo-\text{ }2-\text{ }methylbutane}{\mathop{Br-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}\,\,;}}\,\] \[\underset{2-bromo-\text{ }2-\text{ }methylbutane}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} Br \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\] \[\underset{2-bromo-\text{ }3-\text{ }methylbutane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\overset{\begin{smallmatrix} Br \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\,\,;}}\,\] \[\underset{1-bromo-\text{ }3-\text{ }methylbutane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\]
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