A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
B) \[C{{H}_{3}}C{{O}_{2}}C{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}COC{{H}_{2}}COC{{H}_{3}}\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: C
Solution :
Pentane-2, 4-dione is more acidic than ethanol, because it is an active methylene compound and after the emission of proton, the anion is resonance stabilized.
\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-CH=\overset{\begin{smallmatrix} {{O}^{-}} \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
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