A) 13.3%
B) 11.45%
C) 24.75%
D) 20%
Correct Answer: B
Solution :
Efficiency \[(\eta )=\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{2}}}\] \[=\frac{298-263}{298}=\frac{35}{298}\] = 0.1174 \[=0.1174\times 100\] \[=11.74%\]
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