A) \[[Pt{{(N{{H}_{3}})}_{4}}]C{{l}_{4}}\]
B) \[[Pt{{(N{{H}_{3}})}_{3}}]C{{l}_{3}}\]
C) \[[Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}}]C{{l}_{2}}\]
D) \[[Pt(N{{H}_{3}})C{{l}_{3}}]Cl\]
Correct Answer: C
Solution :
\[\Delta {{T}_{f}}=i{{K}_{f}}m\] or \[i=\frac{\Delta {{T}_{f}}}{{{K}_{f}}\times m}\] \[=\frac{0.0054}{1.86\times 1\times {{10}^{-3}}}\] = 2.9 \[=i\approx 3\] Thus, each molecule of the complex dissociates to form three ions. This can be so only if the formula of the complex is\[[Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}}]C{{l}_{2}}\].
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