A) 7.3 cm
B) 0.9 cm
C) 1.8 cm
D) 3.6 cm
Correct Answer: D
Solution :
The excess pressure inside a air bubble is given by \[P=\frac{2T}{R}\] or \[h\rho g=\frac{2T}{R}\left( \begin{align} & Given:T=72\times {{10}^{-3}}N/m \\ & R=0.4\times {{10}^{-3}}m \\ & {{\rho }_{water}}={{10}^{3}}kg/{{m}^{3}} \\ & g=9.8\,m/{{s}^{2}} \\ \end{align} \right)\] \[h=\frac{2\times 72\times {{10}^{-3}}}{0.4\times {{10}^{-3}}\times {{10}^{3}}\times 9.8}\] \[h=\frac{2\times 72\times {{10}^{-3}}}{0.4\times 9.8}\] \[=36.7\times {{10}^{-3}}m\] \[=36.7\times {{10}^{-3}}\times {{10}^{2}}\,cm\] \[=3.67\,cm\]
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