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EAMCET Medical EAMCET Medical Solved Paper-1996

  • question_answer
    A body thrown up with a velocity reaches a maximum height of 50 m. Another body with double the mass thrown up. With double the initial velocity will reach a maximum height of:

    A)  100 m                                  

    B)  200 m

    C)  10 m                                    

    D)  400 m

    Correct Answer: B

    Solution :

     From the equation of motion. \[{{v}^{2}}={{u}^{2}}-2gh\]at maximum height \[v=0\] Hence,      \[h\propto {{u}^{2}}\]                 \[\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{u_{1}^{2}}{u_{2}^{2}}\] or            \[\frac{50}{{{h}_{2}}}=\frac{u_{1}^{2}}{2u_{1}^{2}}\] \[\therefore \]  \[{{h}_{2}}=4\times 50=200\,m\]


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