A) \[19.6\text{ }cos\text{ }45{}^\circ \]
B) \[19.6\text{ }sin\text{ }45{}^\circ \]
C) \[9.8\text{ }sin\text{ }45{}^\circ \]
D) \[9.8\text{ }cos\text{ }45{}^\circ \]
Correct Answer: B
Solution :
The force of friction required \[f=mg\sin \theta \] \[=2\times 9.8\times \sin {{45}^{o}}\] \[=19.6\sin {{45}^{o}}\]
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