A) will neither rise nor will fall inside the tube
B) will rise inside the tube
C) will rise to the top of the tube
D) will be depressed inside the tube
Correct Answer: A
Solution :
When lower end of a capillary tube touch the liquid, whose angle of contact \[\theta ={{90}^{o}},\] in this situation, the meniscus is plane, hence \[h=0\] \[h=\frac{2T\cos \theta }{r\rho g}=\frac{2T\cos {{90}^{o}}}{r\rho g}=0\] So, the liquid neither rise nor fall in the tube
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