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EAMCET Medical EAMCET Medical Solved Paper-1996

  • question_answer
    A prism of refracting angle \[60{}^\circ \] is made with a material of refractive index \[\mu \].For a certain wavelength of light, the angle of minimum deviation is \[30{}^\circ \]. For this wavelength, the value of u. of material is:

    A)  1.820                                   

    B)  1.503

    C)  1.414                                   

    D)  1.731

    Correct Answer: C

    Solution :

     The value of refractive index of material of prism is \[\mu =\frac{\sin \frac{A+{{\delta }_{m}}}{2}}{\sin \frac{A}{2}}\]                               \[\left( \begin{align}   & \text{Given:}\,{{\delta }_{m}}={{30}^{o}} \\  & A={{60}^{o}} \\ \end{align} \right)\] \[\mu =\frac{\sin \left( \frac{{{60}^{o}}+{{30}^{o}}}{2} \right)}{\sin \frac{{{60}^{o}}}{2}}\] \[=\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}\] \[=\frac{1}{\sqrt{2}}\times \frac{2}{1}\] \[=\sqrt{2}=1.414\]


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