EAMCET Medical EAMCET Medical Solved Paper-1996

  • question_answer
    The field along the axis at a point distance of a short bar magnet is:

    A)  \[I=\frac{{{\mu }_{0}}M}{4\pi {{d}^{2}}}\]                           

    B)  \[I=\frac{{{\mu }_{0}}^{2}M}{4\pi {{d}^{3}}}\]

    C)  \[I=\frac{3{{\mu }_{0}}M}{2\pi {{d}^{3}}}\]                        

    D)  \[I=\frac{{{\mu }_{0}}M}{2\pi {{d}^{3}}}\]

    Correct Answer: D

    Solution :

     Magnetic induction on the axial line (end on position) of a bar magnet is given by \[{{B}_{axis}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2Md}{{{({{d}^{2}}-{{l}^{2}})}^{2}}}\] (when \[l<<d\] for very short bar magnet) \[{{B}_{axis}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}=\frac{{{\mu }_{0}}}{2\pi }\frac{M}{{{d}^{3}}}\]Where M is magnetic moment of magnet.


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