A) 0.025 J
B) 2.5 J
C) 0.0375 J
D) 3.75 J
Correct Answer: C
Solution :
The energy loss when two spheres of different capacitance and potential are connected. \[E=\frac{1}{2}C{{V}^{2}}\Rightarrow E=\frac{1}{2}\left( \frac{{{C}_{1}}{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}} \right)(V_{1}^{2}-V_{2}^{2})\] \[E=\frac{1}{2}\left[ \frac{(3\times 5){{10}^{-12}}}{(3+5){{10}^{-6}}} \right]{{(300-500)}^{2}}\] \[=\frac{1}{2}\times \frac{15}{8}\times {{(-200)}^{2}}\times {{10}^{-6}}\] \[=\frac{15\times 4\times {{10}^{4}}\times {{10}^{-6}}}{16}\] \[=0.0375\,J\]
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