A) \[{{v}^{2}}=Z(a-b)\]
B) v = \[\sqrt{a\,(Z-b)}\]
C) \[v=a\text{ (}Z-b{{\text{)}}^{2}}\]
D) \[~\sqrt{v}=a(Z-b)\]
Correct Answer: D
Solution :
According to Moseleys law the frequency \[(v)\]of characteristic X-ray spectrum is given as \[\sqrt{v}=a(Z-b)\]where a an b are constants for given radiation and Z is the atomic number, Screening constant for \[{{k}_{\alpha }}-line\,b=1\] Screening constant for \[{{L}_{\alpha }}-line\,b=7.4\] Hence, option is correct.
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