EAMCET Medical EAMCET Medical Solved Paper-1996

  • question_answer
    The escape velocity of a sphere of mass m is given   by (G = universal   gravitational constant, M = mass of the earth, Re = radius of the earth):              

    A)  \[\sqrt{\frac{2R{{M}_{e}}}{{{R}_{e}}}}\]              

    B)  \[\sqrt{\frac{2G{{M}_{e}}m}{{{R}_{e}}}}\]

    C)   \[\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}}}\]                                               

    D)  \[\sqrt{\frac{GM}{{{R}_{e}}}}\]

    Correct Answer: A

    Solution :

     Escape velocity of a body, from the surfaces of earth \[{{v}_{e}}=\sqrt{\frac{2G{{M}_{e}}}{{{R}_{e}}}}\] It does not depend on the mass of the body.


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