A) 2.5 min
B) 3.0 min
C) 2.0 min
D) 1.5 min
Correct Answer: C
Solution :
\[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] or \[\frac{{{V}_{1}}/{{t}_{1}}}{{{V}_{2}}/{{t}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] or \[\frac{{{V}_{1}}}{{{t}_{1}}}\times \frac{{{t}_{2}}}{{{V}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] or \[\frac{{{V}_{Hydrocarbon}}}{{{t}_{Hydrocarbon}}}\times \frac{{{t}_{S{{O}_{2}}}}}{{{V}_{S{{O}_{2}}}}}=\sqrt{\frac{{{M}_{S{{O}_{2}}}}}{{{M}_{Hydrocarbon}}}}\] \[{{M}_{S{{O}_{2}}}}=32+32=64\] \[\frac{180}{1.5}\times \frac{{{t}_{S{{O}_{2}}}}}{120}=\sqrt{\frac{64}{16}}\] \[\frac{180\times {{t}_{S{{O}_{2}}}}}{1.5\times 120}=2\] \[{{t}_{S{{O}_{2}}}}=\frac{2\times 1.5\times 120}{180}=2\,\min .\]
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