A) \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}\]
B) \[2S{{O}_{2}}+{{O}_{2}}2S{{O}_{3}}\]
C) \[{{N}_{2}}{{O}_{2}}2NO\]
D) \[{{H}_{2}}+{{I}_{2}}2HI\]
Correct Answer: B
Solution :
\[\begin{align} & 2S{{O}_{2}}+{{O}_{2}}\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,2S{{O}_{3}} \\ & 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\,\,\text{1= 3}\,\text{moles}\,\,\,\,\,\,\,\,\text{2}\,\text{moles} \\ \end{align}\] In the above reaction number reactants has 3 moles and products has 2 moles. So, volume or number of moles decreases in the forward direction. Hence, increase in pressure will favour the reaction in forward direction.
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