A) \[{{C}_{6}}{{H}_{6}}{{O}_{6}}\]
B) \[{{C}_{7}}{{H}_{7}}{{O}_{7}}\]
C) \[{{C}_{3}}{{H}_{6}}{{O}_{2}}\]
D) \[{{C}_{4}}{{H}_{5}}{{O}_{3}}\]
Correct Answer: C
Solution :
% of \[C=\frac{12}{44}\times \frac{\text{wt}\text{.}\,\text{of}\,C{{O}_{2}}}{\text{wt}\text{.of}\,\text{organic}\,\text{compound}}\times 100\] \[=\frac{12}{44}\times \frac{0.361}{0.202}\times 100\] \[=48.78%\] % of \[H=\frac{2}{18}\times \frac{\text{wt}\text{.}\,\text{of}\,{{H}_{2}}O}{\text{wt}\text{.of}\,\text{organic}\,\text{compound}}\times 100\] \[=\frac{2}{18}\times \frac{0.147}{0.202}\times 100\] \[=8.08%\] % of \[\text{O}=100-(%of\,C+%of\,H)\] \[=100-(48.78+8.08)\] \[=43.2%\]| Element | % | At. wt. | \[\frac{\text{ }\!\!%\!\!\text{ }}{\text{At}\text{.wt}\text{.}}\] | Simple Ratio |
| C | 48.78 | 12 | \[\frac{48.78}{12}\] \[=4.06\] | \[\frac{4.06}{2.7}\]\[=1.5\times 2=3\] |
| H | 8.08 | 1 | \[\frac{8.08}{1}=8.08\] | \[\frac{8.08}{2.7}\]\[=3\times 2=6\] |
| O | 43.2 | 16 | \[\frac{43.2}{16}=2.7\] | \[\frac{2.7}{2.7}\]\[=1\times 2=2\] |
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