A) 30.6
B) 147
C) 10.5
D) 60.0
Correct Answer: B
Solution :
Time period is given as \[T=2\pi \sqrt{\frac{l}{g}}\Rightarrow T\propto \sqrt{\frac{l}{g}}\] \[\frac{{{T}_{moon}}}{{{T}_{earth}}}=\sqrt{\frac{{{g}_{earth}}}{{{g}_{moon}}}}=\sqrt{\frac{{{g}_{earth}}}{\frac{{{g}_{earth}}}{6}}}=\sqrt{6}\] \[{{T}_{moon}}=\sqrt{6}\times 1\min =\sqrt{6}\times 60\] \[=146.96s\] \[=147\,s\]
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