question_answer

Ethyl alcohol reacts with bleaching powder to yield:

A)  ethylene            

B)  chloroform

C)  acetone             

D)  ethyl chloride

Correct Answer: B

Solution :

                 Ethyl alcohol reacts with bleaching powder to form chloroform as : \[C{{H}_{3}}C{{H}_{2}}OH+C{{l}_{2}}\xrightarrow{{}}\underset{\text{Chloral}}{\mathop{C{{H}_{3}}CHO}}\,\,+\,HCl\] \[C{{H}_{3}}CHO+3C{{l}_{2}}\xrightarrow{{}}\underset{\text{Chloral}}{\mathop{CC{{l}_{3}}.}}\,CHO+3HCl\]