A) 1.8\[\Omega \]
B) 2.4\[\Omega \]
C) 3.24\[\Omega \]
D) 0.2\[\Omega \]
Correct Answer: B
Solution :
The emf of cell is\[E=V+ir\]Where\[V=0.6V,\,\] P.D. between terminal of the cell connected to a resistance \[R=3\Omega \] \[E=V+\left( \frac{V}{R} \right)r\] \[1.08=0.6+\left( \frac{0.6}{3} \right)r\]Where V = 0.6 V PD between terminal of the cell conected a resistance \[R=3\Omega \] \[0.2r=1.08-0.6=0.48\] \[r=\frac{0.48}{0.2}=2.4\Omega \]You need to login to perform this action.
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