A) 2.5 s
B) 2.6 s
C) 2.4 s
D) 2.2 s
Correct Answer: B
Solution :
Error in the clock is given by \[\Delta T=\frac{1}{2}\alpha (\Delta t)\] Now, error in the clock per day will be \[\Delta \Tau =\frac{1}{2}\alpha (\Delta t)86400\] \[=\frac{1}{2}\times 12\times {{10}^{-6}}\times 5\times 86400\] \[=2.59s=2.6\,s\]You need to login to perform this action.
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