A) \[100{}^\circ C\]
B) 373 K
C) \[373{}^\circ C\]
D) \[-173{}^\circ C\]
Correct Answer: D
Solution :
Ideal gas equation is \[PV=RT\Rightarrow PV\propto T\] Hence, \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{30V}{300}=\frac{1\times 10V}{{{T}_{2}}}\] \[{{T}_{2}}=\frac{300\times 10}{30}=100K=-173{{\,}^{o}}C\]You need to login to perform this action.
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