A) 12.33 MeV
B) 25.75 MeV
C) 37MeV
D) 49.35 MeV
Correct Answer: B
Solution :
The reaction is given as \[4{{\,}_{1}}{{H}^{1}}\to {{\,}_{2}}H{{e}^{4}}+2{{\,}_{1}}e{{\,}^{o}}+energy\] \[4{{\,}_{1}}{{H}^{1}}=4.030372\,\text{amu}\] \[{{\,}_{2}}H{{e}^{4}}=4.002604\,\text{amu}\] \[2\,{{\,}_{1}}{{e}^{o}}=0.001098\,\text{amu}\] Loss in mass or mass defect \[=4.0303720-(4.002604+0.001098)\] \[=0.02667\] Energy released \[=0.02667\times 931\] \[=24.83\,\text{MeV}\]You need to login to perform this action.
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