A) \[\Delta H <\Delta E\]
B) \[\Delta H =\Delta E\]
C) \[\Delta H >\Delta E\]
D) \[\Delta H ,\Delta E\] relation cannot to be predicted
Correct Answer: C
Solution :
Combustion reaction of butanol is : \[{{C}_{4}}{{H}_{9}}OH+6{{O}_{2}}\xrightarrow{{}}4C{{O}_{2}}+5{{H}_{2}}O\] Total no. of moles product = 4 + 5 = 9 Total no. of moles reactant =1+ 6 = 7 \[\Delta n=\]number of moles of products - number of moles of reactants = 9 - 7 = 2means that \[\Delta n\] have +ve value. From the equation \[\Delta H=\Delta E+\Delta n\,RT\] If \[\Delta n=\,0\]then \[\Delta H =\Delta E\] If \[\Delta n=\,-ve\]then \[\Delta H<\Delta E\] If \[\Delta n=+ve\]then \[\Delta H>\Delta E\] In the question \[\Delta n\]has +ve value so, AH>AE. \[\Delta H>\Delta E.\]You need to login to perform this action.
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