A) Diethyl ether \[\xrightarrow{\text{reduction}}X\xrightarrow{SOC{{l}_{2}}}\]
B) Diethyl ether \[+\,\text{HI}\to \]
C) Diethyl ether \[\text{+ PC}{{\text{l}}_{\text{5}}}\to \]
D) Diethyl ether \[\text{+ C}{{\text{l}}_{\text{2}}}\to \]
Correct Answer: D
Solution :
Diethyl ether reacts with chlorine does not give alkyi halide because oxygen atom in diethyl ether is more electronegative than chlorine. Therefore, chlorine cannot break the bond of diethyl ether.You need to login to perform this action.
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