A) 100
B) 25
C) 50
D) 75
Correct Answer: C
Solution :
Acceleration of lift is given by \[{{g}_{1}}=(g\pm a)=(10\pm 5)=15m/{{s}^{2}}\]or \[5\,m/{{s}^{2}}\] Change in the bodys weight \[=m{{g}_{1}}-mg\] (where: mg= initial weight, \[m{{g}_{1}}=\]final weight) \[=(15m-10m)\]or \[(5m-10m)\] Magnitude of change in weight = 5m % change in weight \[=\left| \frac{5m}{10m} \right|\times 100=50%\]You need to login to perform this action.
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