A) \[{{f}_{1}}={{f}_{2}}\frac{2}{3},d=\frac{2}{3}{{f}_{1}}\]
B) \[{{f}_{1}}={{f}_{2}},d={{f}_{1}}+{{f}_{2}}\]
C) \[{{f}_{1}}={{f}_{2}},d=\frac{2}{3}f\]
D) \[{{f}_{1}}=3{{f}_{2}},d={{f}_{1}}+{{f}_{2}}\]
Correct Answer: C
Solution :
It consists of two coaxial plano-convex lenses of equal focal lengths\[{{f}_{1}}\] and \[{{f}_{2}}\] separated by a distance \[\frac{2}{3}f.\] It means, \[{{f}_{1}}={{f}_{2}}\]and \[d=\frac{2}{3}f\]You need to login to perform this action.
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