A) 2 V
B) 4 V
C) 3 V
D) 1 V
Correct Answer: A
Solution :
As \[3\Omega \]AND \[6\Omega \]resistor are connected in parallel, so effective resistance is \[{{R}_{eff}}=\frac{6\times 3}{6+3}=2\Omega \] Again \[{{R}_{eff}}\]is connected in series with another resistor of \[3\Omega .\] Hence, total resistance in the current is \[=2\Omega +3\Omega =5\Omega \] Total current in the circuit \[=\frac{5}{5}=1\,A\] Potential difference across \[3\Omega \] is \[=1\times 3=3\,\text{vot}\] Now, potential difference across \[6\Omega \]resistor \[=5-3=2V\]You need to login to perform this action.
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