EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    A car travelling on a straight track moves with uniform velocity of v1 for same time and with uniform velocity v2 to next equal time. The average velocity is given by:

    A)  \[\sqrt{{{v}_{1}}{{v}_{2}}}\]                                       

    B)  \[\frac{{{v}_{1}}+{{v}_{2}}}{2}\]

    C)  \[{{\left( \frac{1}{{{v}_{1}}}+\frac{1}{{{v}_{2}}} \right)}^{-1}}\]  

    D)         \[2{{\left( \frac{1}{{{v}_{1}}}+\frac{1}{{{v}_{2}}} \right)}^{-1}}\]

    Correct Answer: B

    Solution :

                     Let \[{{s}_{1}}\]and \[{{s}_{2}}\]be the distance travelled by car, then \[{{s}_{1}}={{v}_{1}}t\]                                                                  ?(i) \[{{s}_{2}}={{v}_{2}}t\]                                                                  ?(ii) \[\text{Average}\,\text{velocity =}\frac{\text{total}\,\text{distance}}{\text{tatal}\,\text{time}\,\text{taken}}\] \[=\frac{{{s}_{1}}+{{s}_{2}}}{t+t}=\frac{{{v}_{1}}t+{{v}_{2}}t}{2t}\] \[=\frac{{{v}_{1}}+{{v}_{2}}}{2}\]


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