2. Solved Papers
  3. EAMCET Medical

EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    A lift is moving with a retardation of \[5\text{ }m/{{s}^{2}}.\] The percentage change in the weight of person in the lift is \[(g=10m{{s}^{-2}}):\]

    A)  100                                       

    B)  25

    C)  50                                         

    D)  75

    Correct Answer: C

    Solution :

                     Acceleration of lift is given by \[{{g}_{1}}=(g\pm a)=(10\pm 5)=15m/{{s}^{2}}\]or \[5\,m/{{s}^{2}}\] Change in the bodys weight \[=m{{g}_{1}}-mg\]  (where: mg= initial weight, \[m{{g}_{1}}=\]final weight) \[=(15m-10m)\]or \[(5m-10m)\] Magnitude of change in weight = 5m % change in weight \[=\left| \frac{5m}{10m} \right|\times 100=50%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner