A) 2 P
B) P
C) \[\frac{P}{2}\]
D) 4 P
Correct Answer: A
Solution :
\[\left( \begin{align} & Given:{{P}_{A}}={{P}_{B}}=P \\ & {{V}_{A}}={{V}_{B}}={{V}_{mixture}}=V \\ & {{T}_{A}}={{T}_{B}}={{T}_{mixture}}=T \\ \end{align} \right)\] From the relation, \[PV=RT\] \[\frac{{{P}_{mix}}V}{T}=\frac{{{P}_{A}}{{V}_{A}}}{{{T}_{A}}}+\frac{{{P}_{B}}+{{V}_{B}}}{{{T}_{B}}}\] \[=\frac{PV}{T}+\frac{PV}{T}=\frac{2PV}{T}\] So, \[{{P}_{mixture}}=2P\]
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