EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    A piano convex lens is made of refractive index 1.6. The radius of curvature of the curved surface is 60 cm. The focal length of the lens is:

    A)  50 cm                                  

    B)  100 cm

    C)  200 cm                                

    D)  400 cm

    Correct Answer: B

    Solution :

                     The focal length of a lens is given by \[\frac{1}{f}=(\mu -1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] \[\left( \begin{align}   & \text{where:}\,\text{R = }\infty  \\  & {{R}_{2}}=-60\,cm \\  & \mu =1.6 \\ \end{align} \right)\] \[\frac{1}{f}=\left( 1.6-1 \right)\left( \frac{1}{\infty }=-\frac{1}{-60} \right)\] \[\frac{1}{f}=0.6\times \frac{1}{60}=\frac{1}{100}\]                 \[\Rightarrow \]               \[f=100\,cm\]


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