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EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    A wheel of mass 10 kg has a moment of inertia of \[160\text{ }kg-{{m}^{2}}\]about its own axis. The radius of gyration is:

    A)  10 m                                    

    B)  4 m

    C)  5 m                                       

    D)  6 m

    Correct Answer: B

    Solution :

                     The moment of inertia of wheel about its own axis is given by \[I=m{{K}^{2}}\]                                               ?(i) where, K = Radius of gyration Given:  \[I=160\,kg-{{m}^{2}}\] Now, putting the given values in Eq (i) \[160=10{{K}^{2}}\] \[{{K}^{2}}=\frac{160}{10}\Rightarrow K=4m\]


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