A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{8}\]
Correct Answer: D
Solution :
No. of half - lives n \[n=\frac{t}{T}=\frac{72000}{24000}=3\] From relation, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{3}}=\frac{1}{8}\]You need to login to perform this action.
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