A) 10 m
B) 4 m
C) 5 m
D) 6 m
Correct Answer: B
Solution :
The moment of inertia of wheel about its own axis is given by \[I=m{{K}^{2}}\] ?(i) where, K = Radius of gyration Given: \[I=160\,kg-{{m}^{2}}\] Now, putting the given values in Eq (i) \[160=10{{K}^{2}}\] \[{{K}^{2}}=\frac{160}{10}\Rightarrow K=4m\]You need to login to perform this action.
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