A) zero
B) 7.5 kg
C) 2.5 kg
D) 6 kg
Correct Answer: D
Solution :
According to Boyles law PV = constant (at constant temperature) \[\Rightarrow \] \[P\propto \frac{1}{V}\Rightarrow P\propto \frac{1}{m/d}\Rightarrow P\propto \frac{1}{m}\] Hence , \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\] \[\left( \begin{align} & \text{Given: }{{\text{P}}_{1}}={{10}^{7}}N/{{m}^{2}} \\ & {{P}_{2}}=25\times {{10}^{7}}N/{{m}^{2}} \\ & {{m}_{1}}=10\,kg \\ \end{align} \right)\] \[\frac{{{10}^{7}}}{2.5\times {{10}^{7}}}=\frac{{{m}^{2}}}{10}\] So, \[{{m}_{2}}=\frac{10}{2.5}=4\,kg\] Quantity of gas taken out is \[=10-4=6\,kg\]You need to login to perform this action.
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