A) \[\pi \times {{10}^{-10}}T\]
B) \[\pi \times {{10}^{-9}}T\]
C) \[\frac{\pi }{2}\times {{10}^{-10}}T\]
D) \[\frac{\pi }{2}\times {{10}^{-9}}T\]
Correct Answer: A
Solution :
Here: \[q={{10}^{-6}}C\] \[t=1s\] \[n=5\,rev/s\] \[r={{10}^{-2}}m\] The magnetic induction field at the centre of circular path is given by \[B=\frac{{{\mu }_{0}}i}{2r}=\frac{{{\mu }_{0}}nq}{2r\times t}\] \[=\frac{4\pi \times {{10}^{-7}}\times 5\times {{10}^{-6}}}{2\times {{10}^{-2}}\times 1}\] \[=10\pi \times {{10}^{-11}}=\pi \times {{10}^{-10}}\]tesla
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